Finding the specific latent heat of fusion of an ice cube

[kiro484]

Homework Statement

We completed a lab with the following information

Substance Mass(g) Starting temperature (°C) Final Temperature (°C)
Ice cube 15.55 0 12
Water 151.25 21 12

Now we need to find the specific latent heat of fusion of water

Homework Equations

Q=mcΔt
Q=mH or Q=mL

The Attempt at a Solution

Heat Loss(water)=Heat Gain(ice cube)
mcΔt(water)=mH+mcΔt(ice cube)
Solving for H
H=mcΔt (water)
m+mcΔt (ice cube)

H=(151.25)(4.2)(9)
15.55+15.55(4.2)12

H=5717.25
799.27

This gives me an answer which is nowhere near the actual value of the specific latent heat of fusion of water.
Any help would be greatly appreciated, thanks in advance

 

[CWatters]

Heat Loss(water)=Heat Gain(ice cube)
mcΔt(water)=mH+mcΔt(ice cube)
Solving for H
H=mcΔt(water)
m+mcΔt (ice cube)

Have you rearranged that correctly?...

m_wcΔt_w = m_iH+m_icΔt_i

so..

m_iH = m_wcΔt_w - m_icΔt_i

and

H = (m_wcΔt_w - m_icΔt_i)/m_i