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Finding the specific latent heat of fusion of an ice cube

  1. Nov 5, 2012 #1
    1. The problem statement, all variables and given/known data
    We completed a lab with the following information

    Substance Mass(g) Starting temperature (°C) Final Temperature (°C)
    Ice cube 15.55 0 12
    Water 151.25 21 12

    Now we need to find the specific latent heat of fusion of water


    2. Relevant equations
    Q=mcΔt
    Q=mH or Q=mL


    3. The attempt at a solution
    Heat Loss(water)=Heat Gain(ice cube)
    mcΔt(water)=mH+mcΔt(ice cube)
    Solving for H
    H=mcΔt (water)
    m+mcΔt (ice cube)

    H=(151.25)(4.2)(9)
    15.55+15.55(4.2)12

    H=5717.25
    799.27

    This gives me an answer which is nowhere near the actual value of the specific latent heat of fusion of water.
    Any help would be greatly appreciated, thanks in advance
     
  2. jcsd
  3. Nov 6, 2012 #2

    CWatters

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    Science Advisor
    Homework Helper

    Have you rearranged that correctly?...

    mwcΔtw = miH+micΔti

    so..

    miH = mwcΔtw - micΔti

    and

    H = (mwcΔtw - micΔti)/mi
     
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