Finding the Standard Deviation from Probability

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To find the standard deviation (σ) for the random variable X given P(X≤500)=0.5 and P(X>650)=0.0227, it's essential to assume a specific probability distribution, such as the normal distribution. The median of the distribution is at 500, indicating that half of the values are below this point. The probability of X being between 500 and 650 is 47.73%. By dividing the integral for variance into three parts based on these probabilities, one can calculate the standard deviation. This approach highlights the relationship between standard deviation and the given probabilities.
Samwise_geegee
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Homework Statement



For a certain random variable X, P(X≤500)=.5 and P(X>650)=.0227, find σ.



Homework Equations



μ=expected value=mean

Variance=∫(X-μ)2fx(X)dx evaluated from -∞ to ∞

σ=√Variance



The Attempt at a Solution



I'm not sure what the relationships between the standard deviation and the probabilities given are.
My only guess is that P(X≤500)=.5 also fits the definition for the median of this function but I'm not sure where the median fits into the standard deviation either. Any help is appreciated!
 
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Samwise_geegee said:

Homework Statement



For a certain random variable X, P(X≤500)=.5 and P(X>650)=.0227, find σ.



Homework Equations



μ=expected value=mean

Variance=∫(X-μ)2fx(X)dx evaluated from -∞ to ∞

σ=√Variance



The Attempt at a Solution



I'm not sure what the relationships between the standard deviation and the probabilities given are.
My only guess is that P(X≤500)=.5 also fits the definition for the median of this function but I'm not sure where the median fits into the standard deviation either. Any help is appreciated!

The question as written does not allow for a unique solution. You need to assume a form of probability distribution, such as Normal or Poisson or Gamma or ... . I suggest you try it for the case of normally-distributed X.
 
So you have a 50% chance of X being less than or equal to 500, and a 2.27% chance of it being greater than 650. That means there's a 47.73% chance for 500 < X <= 650. Now, knowing this you should be able to divide your integral into three separate integrals, as you now know the PDF values for each region.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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