Finding the Sum of a Convergent Power Series

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SUMMARY

The forum discussion focuses on evaluating the sum of the convergent power series ∑ n².xⁿ for 0 < x < 1. Participants establish that the radius of convergence is R = 1, confirming the series converges for |x| < 1. The discussion emphasizes the importance of differentiating known series, specifically starting with the geometric series ∑ xⁿ, to derive the desired function f(x) = ∑ n².xⁿ. The integration and differentiation methods are debated as effective strategies for solving the series.

PREREQUISITES
  • Understanding of power series and convergence criteria
  • Familiarity with differentiation and integration techniques in calculus
  • Knowledge of the geometric series ∑ xⁿ
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of the geometric series ∑ xⁿ and its applications
  • Learn about the method of differentiating power series to find sums
  • Explore integration techniques for power series
  • Investigate the properties of convergent series and their radius of convergence
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Students and educators in calculus, mathematicians interested in series convergence, and anyone looking to deepen their understanding of power series evaluation techniques.

mathmathmad
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Homework Statement



evaluate ∑ n^2.x^n where 0<x<1

Homework Equations





The Attempt at a Solution


let a_n = n^2 and c=0
then radius of convergence, R=1
hence the series convergences when |x|<1
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity

from here, how to I derive a function ∑ (n+1)^3.x^n so as to integrate it to get the sum?
 
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Hi mathmathmad! :smile:

(have an infinity: ∞ and try using the X2 and X2 tags just above the Reply box :wink:)
mathmathmad said:
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity …

Why are you making it more complicated? :redface:

Hint: try integrating. :wink:
 
differentiating is a much better option fyi
 
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
 
what to integrate?
intergrate n^2.x^n?
 
mathmathmad said:
what to integrate?
intergrate n^2.x^n?

Sort-of.

Suppose it was ∑ nxn … what would you integrate? :wink:
 
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.
 
Hi Mathnerdmo! :smile:
Mathnerdmo said:
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
Mathnerdmo said:
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.

ah, i see what you mean now …

your method is basically the same as mine, but in reverse …

i'm integrating the question to try to get something easier, while you're starting with something easier, and differentiating to get the question. :wink:

Yes, if mathmathmad wants to start with ∑ xn and differentiate it, that's fine. :smile:
 

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