Finding the Sum of a Series: n/2^n

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The discussion focuses on finding the sum of the series defined by the summation of n/2^n from n=1 to infinity. Participants suggest using the formula for the geometric series, but there is uncertainty about how to handle the extra n in the numerator. Differentiating the geometric series summation formula is proposed as a potential method, with the suggestion to set x=1/2. The need for uniform convergence to justify this differentiation is raised, indicating a deeper understanding of series convergence is necessary. Ultimately, the conversation highlights the challenges in calculating the sum and the methods that could be employed to approach the problem.
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Homework Statement



Find the sum of the series.

Summation (n/2^n)
from n = 1 to inf

Homework Equations



Summation (x^n) = 1/1-x

The Attempt at a Solution



n/2^n
n*(1/2)^n

Not sure what this equals after this... I was thinking (1/1-0.5) but that is a guess.
There are other ones like this, i have no idea how to do them, so any help on how to start and/or finish them will be appreciated.
 
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Have you covered uniform convergence of series?
 
I...don't know. Ik that the terms themselves converge to zero, but I don't know how to calc the sum...
 
Differentiate Summation(x^n)=1/(1-x). Put x=1/2.
 
This is what I had in mind, but don't we need uniform convergence to justify differentiating under the sum?

I remember doing this problem w/o this trick a year ago. It involved rearanging the series if my memory serves me right.
 
What do I do about the extra n in front then?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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