Finding the Sum of A + \sqrt{A^2 - B^2} and U + \sqrt{U^2 - V^2}

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The discussion focuses on finding the sum of the expressions A + √(A² - B²) and U + √(U² - V²), where A, B, U, and V are real numbers. The goal is to express the result in the form x + √(x² - y²), with x dependent on A and U, and y dependent on B and V. It is noted that A represents the arithmetic mean of the roots of a quadratic equation, while B is the geometric mean. The discussion concludes that there is no unique solution, and one can set x = y equal to the left side of the equation for simplification.

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Bruno Tolentino
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Given two numbers: [tex]A + \sqrt{A^2 - B^2}[/tex] and [tex]U + \sqrt{U^2 - V^2}[/tex] OBS: A, B, U and V are real numbers.

I want sum it and express the result in the same form: [tex]A + \sqrt{A^2 - B^2} + U + \sqrt{U^2 - V^2} = x + \sqrt{x^2 - y^2}[/tex] So, x depends of A and U. And y depends of B and V:
[tex]x = x(A, U)[/tex] [tex]y = y(B, V)[/tex] Do have any ideia about how do it?

PS: A is the arithmetic mean of the roots of the quadratic equation and B is the geometric mean. Is a nice expression for the quadratic formula!
 
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There is no unique solution. You can simply set x=y= [left side of the equation], for example. And I don't see any special solution sticking out.
 

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