Finding the third force for equilibrium of three forces

[triplel777]

Homework Statement

Three forces are applied to an object. Force F1 has a magnitude of 23.0 Newtons (23.0 N) and is directed 30.0° to the left of the +y axis. Force F2 has a magnitude of 14.0 N and points along the +x axis. What must be the magnitude and direction (specified by the angle θ in the drawing) of the third force F3 such that the vector sum of the three forces is 0 N?

Homework Equations

The Attempt at a Solution

i have no idea where to even start..please help me!

 

[kuruman]

Do you know how to resolve vectors into components? If, "yes", do it and make sure that all x-components together add to zero and all the y-components together add to zero. If "no", you should learn that first before attempting this problem.

 

[triplel777]

ok so for x it was +14 and for y it was -23-x.so i did the square root of (-23-x)^2 +14^2
resulting in -27 N. but that is the wrong answer

 

[kuruman]

ok so for x it was +14 and for y it was -23-x.so i did the square root of (-23-x)^2 +14^2
resulting in -27 N. but that is the wrong answer

I cannot understand what "it" is that was +14 for x or -23-x for y. Let me see two separate equations, one below the other. Equation 1 should say that the sum of all the x-components is zero and Equation 2 should say that the sum of all the y-components is zero.