What is the Magnitude of Betty's Force for Equilibrium?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 3K views
J-dizzal
Messages
394
Reaction score
6

Homework Statement


FC of magnitude 188 N. Note that the direction of FC is not given. What is the magnitude of Betty's force FB if Charles pulls in (a) the direction drawn in the picture or (b) the other possible direction for equilibrium

Homework Equations


ΣF=0[/B]

The Attempt at a Solution


20150623_181903_zpsqwl2uqe2.jpg

Im having trouble with part b) of the question. I don't know what other possiblities there are.
 
Physics news on Phys.org
phinds said:
I can't see any of your images. Are they embedded or linked?

updated
 
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
 
americanforest said:
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
oh its so obvious now thanks