1. A block with a mass of 6 kg is held in equilibrium on an inclined plane of angle θ=30 degrees by a horizontal force F. Find the magnitudes of normal force on the block and of F (ignore friction). So far, I've found Fg=6(-9.81)=-58.86 N I then found Fgy=-58.86(sin240)=50.97 and Fgx=-58.86(cos240)=29.43 And I know that, since the block is in equilibrium, Fnet=0, so 0=Fn + Fgy + Fay I just seem to be having the problem of finding applied force so that I can find Fn and Fay. Any help would be greatly appreciated! Thanks in advance.