Finding the time of arrival between two balls in air using kinematics

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
5 replies · 3K views
garcia1
Messages
27
Reaction score
0

Homework Statement


A ball is thrown upward from the ground with
an initial speed of 51 m/s; at the same instant,
a ball is dropped from a building 38 m high.
After how long will the balls be at the
same height? The acceleration of gravity is
9.8 m/s2 .
Answer in units of s.


Homework Equations



Equations of Kinematics


The Attempt at a Solution


I thought that by finding the time difference between the two that it would give me the answer.

Setting up the equation as DeltaT = T1 - T2, I found the times for each object using equation Vf = Vi + at for the object with a velocity of 51m/s, and the equation x = Vo*t + 1/2at^2 for the object 38 meters above the ground. Finding the time for these two, I plugged them into my DeltaT equation, with the biggest value as T1.

I got the answer 2.42s, but this was wrong.
 
Physics news on Phys.org
hi garcia1! :wink:
garcia1 said:
Setting up the equation as DeltaT = T1 - T2, I found the times for each object using equation Vf = Vi + at for the object with a velocity of 51m/s …

i don't understand … how do you know Vf ? :confused:

why not use the same equation for both balls (with different x0 and v0 of course)? :smile:
 
What I thought you meant by this was that I should set both equations equal to a common variable, and then solve for T accordingly. I tried this with the variable Vf, solving for both in this way:

Eq 1: Vf = Vo +at
Eq 2: Vf^2 = Vo^2 + 2ax -> Vf = rad(Vo^2 + 2ax)

Then setting them equal to each other: Vo + at = rad(Vo^2 + 2ax) - Vo
a

I solved for t, and got the answer T = 2.42s, but this was wrong. Any thoughts on where I messed up?
 
The second equation is over a. Sorry, computing error.
 
You're trying to find when both balls will be at the same height. So wouldn't it be a good idea to write an equation for each ball which gives the height at a given time and then equate them?
 
hi garcia1! :smile:

(just got up :zzz: …)
garcia1 said:
What I thought you meant by this was that I should set both equations equal to a common variable, and then solve for T accordingly. I tried this with the variable Vf …

but that will only give you the time T at which they both have the same velocity, won't it? :wink: