Finding the time of arrival between two balls in air using kinematics

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Homework Help Overview

The problem involves two balls: one thrown upward from the ground with an initial speed of 51 m/s and another dropped from a height of 38 m. The objective is to determine the time at which both balls reach the same height, considering the acceleration due to gravity is 9.8 m/s².

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting up equations for each ball to find the time they are at the same height. There is an exploration of using different kinematic equations and questioning the use of final velocity (Vf) in the calculations.

Discussion Status

Some participants are attempting to equate the height equations for both balls to find a common time. There is recognition of potential errors in previous calculations, and suggestions to clarify the approach to finding the time when both balls are at the same height.

Contextual Notes

Participants are navigating through the kinematic equations and discussing the implications of using different initial conditions for each ball. There is an acknowledgment of the need to ensure the equations reflect the correct physical scenario.

garcia1
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Homework Statement


A ball is thrown upward from the ground with
an initial speed of 51 m/s; at the same instant,
a ball is dropped from a building 38 m high.
After how long will the balls be at the
same height? The acceleration of gravity is
9.8 m/s2 .
Answer in units of s.


Homework Equations



Equations of Kinematics


The Attempt at a Solution


I thought that by finding the time difference between the two that it would give me the answer.

Setting up the equation as DeltaT = T1 - T2, I found the times for each object using equation Vf = Vi + at for the object with a velocity of 51m/s, and the equation x = Vo*t + 1/2at^2 for the object 38 meters above the ground. Finding the time for these two, I plugged them into my DeltaT equation, with the biggest value as T1.

I got the answer 2.42s, but this was wrong.
 
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hi garcia1! :wink:
garcia1 said:
Setting up the equation as DeltaT = T1 - T2, I found the times for each object using equation Vf = Vi + at for the object with a velocity of 51m/s …

i don't understand … how do you know Vf ? :confused:

why not use the same equation for both balls (with different x0 and v0 of course)? :smile:
 
What I thought you meant by this was that I should set both equations equal to a common variable, and then solve for T accordingly. I tried this with the variable Vf, solving for both in this way:

Eq 1: Vf = Vo +at
Eq 2: Vf^2 = Vo^2 + 2ax -> Vf = rad(Vo^2 + 2ax)

Then setting them equal to each other: Vo + at = rad(Vo^2 + 2ax) - Vo
a

I solved for t, and got the answer T = 2.42s, but this was wrong. Any thoughts on where I messed up?
 
The second equation is over a. Sorry, computing error.
 
You're trying to find when both balls will be at the same height. So wouldn't it be a good idea to write an equation for each ball which gives the height at a given time and then equate them?
 
hi garcia1! :smile:

(just got up :zzz: …)
garcia1 said:
What I thought you meant by this was that I should set both equations equal to a common variable, and then solve for T accordingly. I tried this with the variable Vf …

but that will only give you the time T at which they both have the same velocity, won't it? :wink:
 

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