Finding the Total Charge of a Non-Uniformly Charged Disc

Click For Summary

Homework Help Overview

The problem involves a disc with a radius R that has a non-uniform charge distribution, where one half has a charge density of +2σ and the other half has a charge density of -σ. The objective is to determine the total charge of the disc.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the interpretation of the problem, particularly whether the "half" refers to half of the radius or half of the surface area. There are attempts to clarify the setup and the implications of the charge distribution on the total charge calculation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem statement. Some guidance has been offered regarding the assumptions about the charge distribution, but no consensus has been reached on the correct approach to take.

Contextual Notes

There are uncertainties regarding the definition of "half" in the context of the charge distribution, as well as the completeness of the problem statement. Participants express concerns about how the area of the disc varies with radius, which may affect the calculations.

Hatyk
Messages
6
Reaction score
0

Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
 
Physics news on Phys.org
Well, in my opinion the statement of problem not say if the half is the half of radius or the half of surface. My intuition says the half of surface, but you can make the two cases
 
Statement of the problem is not complete. Which two halves are we talking about?
 
Hatyk said:

Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
I see nothing wrong with your assumption. I'll go on a limb and say it doesn't matter if the charges are all +2s on one side and -s on the obverse side, vs. each side has half +2s and the other half -s.
 
Last edited:
How about half the radius with +2σ and the other half with -σ?
 
Chandra Prayaga said:
How about half the radius with +2σ and the other half with -σ?
Personally I'd have some difficulty justifying that given how the area of a disk varies with the radius :smile:
 
  • Like
Likes   Reactions: rude man

Similar threads

Replies
1
Views
896
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 27 ·
Replies
27
Views
3K
Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
12
Views
2K
Replies
44
Views
4K