Finding the Total mechanical energy

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SUMMARY

The discussion focuses on calculating the total mechanical energy of a shot putter's shot, specifically a 5.00 kg shot released at a height of 2.00 m with an initial velocity of 15.0 m/s. The total mechanical energy at the moment of release is determined to be 661 J, which is the sum of potential energy and kinetic energy at maximum height. The calculations involve using the formulas for potential energy (PE = mgh) and kinetic energy (KE = 0.5mv²). The final answers for potential and kinetic energy at maximum height were confirmed as necessary to find the total mechanical energy.

PREREQUISITES
  • Understanding of gravitational potential energy (PE = mgh)
  • Knowledge of kinetic energy (KE = 0.5mv²)
  • Basic principles of mechanics and energy conservation
  • Ability to perform algebraic calculations with units of mass, height, and velocity
NEXT STEPS
  • Review the principles of energy conservation in mechanical systems
  • Explore advanced applications of potential and kinetic energy in projectile motion
  • Learn about the effects of air resistance on mechanical energy calculations
  • Study the concepts of work and energy in physics for deeper understanding
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Physics students, educators, and anyone interested in mechanics and energy calculations in projectile motion scenarios.

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At the moment when a shot putter releases a 5.00 kg shot, the shot is 2.00 m above the ground and traveling at 15.0 m/s. It reaches a maximum height of 8.00 m above the ground and then falls to the ground. Assume that air resistance is negligible.

a. What was the potential energy of the shot as it left the hand, relative to the ground?
b. What was the kinetic energy of the shot as it left the hand?
c. What was the total mechanical energy of the shot as it left the hand?
d. What was the total mechanical energy of the shot as it reached its maximum height?
e. What was the potential energy of the shot at its maximum height?
f. What was the kinetic energy of the shot at its maximum height?
g. What was the kinetic energy of the shot just as it struck the ground?

I've got the answers up until question c). But I've been stuck on d) I know the answer is 661 J but I don't know how








The Attempt at a Solution

 
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sum answers e and f to get d
 
Thanks got it!
 

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