Q7. Some lead shot with a mass of 50 grams is placed into a card board box the distance from one end to the other being 1m. The ends are sealed with rubber bungs in order to prevent the lead shots from falling out, the tube is rotated so the lead shots fall down from one end to hit the rubber bung at the opposite end.
A) A student rotates the tube 50 times. Calculate the total decrease in the gravitational potential energy store of the lead shot in the process.
B) The Specific Heat Capacity of the lead shots is 160J/kg°c . Calculate the rise in temperature after the tube has been rotated 50 times.
C) Why is the temperature rise of the lead shot likely to be less than what was calculated in part B.
Gravitational potential energy = mass x gravitational field strength x height
Change in temperature= Change in energy / mass x specific heat capacity
Final GPE - Initial GPE[/B]
The Attempt at a Solution
Question A ) Firstly, I had calculated the initial GPE of the lead shots which I had derived to be 0.5J ( Note: The value 10 was used for gravitational field strength) as I had done GPE = 0.05kg x 10N/M x 1m. As for the second value because it was said to be flipped 50 times I had multiplied the height by 50, this meant that I did GPE= 0.05kg x 10N/M x 50 = 25J . Assuming the second set of values is the final GPE I did 25J - 0.5J= 24.5J lost
As for the other two questions I could not think of anything.