- #1

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- 47

## Homework Statement

Here's a link to the website that has the problem. It's right under example 1.

http://www.sparknotes.com/testprep/books/sat2/physics/chapter6section3.rhtml

## Homework Equations

## The Attempt at a Solution

This is just for the first part; finding Curly's force.

For the sled not to move up or down, both Curly and Moe will each have to have a y component force that cancels out the other one. I calculated Moe's y component force to be 17.32 N, which means Curly would also have to have 17.32 N of downward force to negate Moe's force. Then I calculated Curly's x component of force from having his y component of force and got 29.999 N of force.

What they did is completely foreign to me. First, they got 8.660 N as Moe's y component of force because they multiplied .866, the sine, times the x component. I don't know why they did that.

Then they just divided the 8.660 they got by Curly's sine to get Curly's x component of force. I don't see why they did that and they don't explain why they were doing it.

Thanks.