# Finding the value of k (spring constant)

• p0ps1c1e
In summary, the value of the spring constant for the ideal very light spring that has been stretched 1.4m and requires 100J of work to stretch an additional 1.5m is 31 N/M. This is calculated by finding the total work done to stretch the spring, which is equal to the sum of the work done to stretch it 1.4m and the work required to stretch it an additional 1.5m. This total work is then set equal to the potential energy stored in the spring, which is represented by 1/2kx^2. Solving for k gives a value of 31 N/M.

#### p0ps1c1e

During a test experiment, the engineer finds an ideal very light spring has already been stretched 1.4m from its original length. He also finds that he needs to perform 100J of work to further stretch this spring an additional 1.5m. What is the value of the spring constant for this spring?

## Homework Equations

W = F*d

F = -kx

So I wrote out that F1 = -kx to stretch the spring the initial 1.4m and then to stretch it the additional 1.5m it would take:

F2 +F1 = -2.9*k

I also wrote out:

F1 = -1.5k

Then I used 100 = F2*1.5

so F2 = 66.67 although I'm not sure if you can use this equation for a spring

Then 66.67 -1.5k = -2.9k and I tried solving for k but that didn't work so I'm not sure what else to try.

p0ps1c1e said:
Then I used 100 = F2*1.5
There are two problems with that approach. First, your F2 is the additional force to get the extra 1.5m extension, but while extending it that 1.5m the total force applied is between F1and F1+F2. Therefore F1is an important part of the work done.
Secondly, the force only reaches F1+F2 at full extension, so neither can you write 100 = (F1+F2)*1.5.

In terms of k, what work was done to stretch it 1.4m? What total work was done to stretch it 1.4+1.5m?

So W1 = 1/2k*(1.4)^2 = 0.98k
W2 = 100
WorkTotal = 1/2k(2.9)^2 = 4.205k

Then I put it together 4.205k = 0.98k + 100J

so k = 31 N/M ?

Also, I thought 1/2kx^2 was for potential energy of a spring. So I'm kind of confused about the difference between the two now

p0ps1c1e said:
so k = 31 N/M ?
Looks right.
p0ps1c1e said:
I thought 1/2kx^2 was for potential energy of a spring.
The work done to stretch a spring (from slack) equals the potential energy stored in the spring (assuming no losses). Where's the confusion?

Thanks. I guess I just need to review this chapter some more