Finding the Value of Σk=0k=7a2k from a Multinomial Expansion

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SUMMARY

The discussion centers on calculating the value of Σk=0k=7a2k from the multinomial expansion of (1+x+x²+x³)⁵. The user initially evaluates the expression by substituting x=1 and x=-1, leading to the equations 45 = a0 + a1 + a2 + ... + a15 and 0 = a0 - a1 + a2 - ... - a15. After combining these results, the user concludes that Σk=0k=7a2k equals 256, but the correct answer is 512, indicating a miscalculation in their approach to the multinomial coefficients.

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Homework Statement



If (1+x+x2+x3)5 = Σk=0k=15akxk, then Σk=0k=7a2k is equal to?

The Attempt at a Solution



Put x=1 in the expression given. We get
45 = a0 + a1 + a2 + ... a15

Put x=-1 in the same expression
0 = a0 - a1 + a2 ... -a15

Adding the two results,
45 = 2(a0 + a2...a14)

So Σk=0k=7a2k = 44 = 256.

The answer given is 512. Can somebody point out my mistake?
 
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Why do you think 4^5/2 is equal to 4^4??
 


lol I don't think so. That's a silly mistake :redface:
 

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