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Finding the Vector Eqn of a Line

  1. Sep 20, 2009 #1
    1. The problem statement, all variables and given/known data

    Find the Vector eqn of a line which passes through P(2, -1, 3) and is perpendicular to the plane 3x -2y -z =0.

    2. Relevant equations

    Line(x) = P + td where d is a direction vector

    3. The attempt at a solution

    My main problem here is trying to find the direction vector for the line. I have really no idea how to find that. Any help is greatly appreciated :)
     
  2. jcsd
  3. Sep 20, 2009 #2
    I think I figured it out...I can use the normal vector of the plane as my direction vector.
     
  4. Sep 20, 2009 #3

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Yes, that's exactly right. And that, of course, is just 3i- 2j- k.
     
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