Finding the Vector Eqn of a Line

1. Sep 20, 2009

d=vt+1/2at^2

1. The problem statement, all variables and given/known data

Find the Vector eqn of a line which passes through P(2, -1, 3) and is perpendicular to the plane 3x -2y -z =0.

2. Relevant equations

Line(x) = P + td where d is a direction vector

3. The attempt at a solution

My main problem here is trying to find the direction vector for the line. I have really no idea how to find that. Any help is greatly appreciated :)

2. Sep 20, 2009

d=vt+1/2at^2

I think I figured it out...I can use the normal vector of the plane as my direction vector.

3. Sep 20, 2009

HallsofIvy

Staff Emeritus
Yes, that's exactly right. And that, of course, is just 3i- 2j- k.