Does the line lie in the plane?

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SUMMARY

The line through the point P(1, 2, 3) with direction vector d = (1, 2, -3) does not lie in the plane defined by the equation 2x + y - z = 3. The vector normal to the plane is (2, 1, -3), and the dot product of this normal vector with the direction vector of the line is not zero, confirming that the line is not parallel to the plane. Additionally, point P does not satisfy the plane equation, further establishing that the line does not lie in the plane.

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  • Understanding of vector mathematics
  • Knowledge of plane equations in three-dimensional space
  • Familiarity with dot product calculations
  • Basic concepts of linear algebra
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  • Learn about the implications of dot products in determining parallelism
  • Explore methods for verifying point-plane relationships
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Homework Statement


Does the line through the point P(1, 2, 3) with direction vector d = (1, 2, -3) lie in the plane 2x+y-z=3?

Homework Equations

The Attempt at a Solution


From the 2x+y-z i can get the vector (2, 1, -3) and the direction vector, their dot product does not equal zero. So, no it does lie on the plane. Just wondering if my intuition is correct.
 
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Yes because, as you might have added, ##\langle 2,1,3\rangle## is perpendicular to the plane. Or you might have noticed that P isn't in the plane in the first place.
 

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