Finding the Zero Point of Electric Field from a Dipole Configuration

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SUMMARY

The discussion centers on determining the coordinate along the x-axis where the electric field produced by two fixed charges, q1 and q2, equals zero. Charge q1 is 2.91 x 10-8 C located at 26.3 cm, while charge q2 is -5.82 times q1, positioned at 46.6 cm. The participant correctly identifies the need to use Coulomb's law to express the electric fields from both charges as functions of x and set their sum to zero to find the zero point of the electric field.

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czaitz
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I'd like to check my thinking which is getting fuzzy:

Question: Two particles are fixed to an x axis: particle 1 of charge q1 = 2.91 x 10-8 C at x = 26.3 cm and particle 2 of charge q2 = -5.82q1 at x = 46.6 cm. At what coordinate on the x-axis is the electric field produced by the particles equal to zero?

I am thinking: q1=2.91E-8C and q2=-1.694E-7C . I found the net electric field by using Coulomb's law, which is .0013 N/C. Now I need to find where the net E field is zero, and I thought that if I set E=0 I could find the r where E=0 but I can't seem to figure out how to do that. I can't just substitute E to find r ...I know it's not that hard but I'm experiencing a block...
 
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Your net electric field shouldn't be a constant, it should be a function of x (or r, but you're only considering the one direction). It should be the sum of two electric fields, one from q1, one from q2. Then set it equal to zero and solve for x.
 
Well, gosh, that makes sense! thanks!
 

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