Finding thickness of a thin film question

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SUMMARY

The discussion focuses on calculating the thickness of a thin oil film (n = 1.23) on wet pavement, which reflects red light at 640 nm and no light at 569 nm. The correct formulas for interference are established: constructive interference is given by 2nt = mλ, while destructive interference is represented as 2nt = (m - 1/2)λ. The participants confirm that both sets of equations are valid, with the distinction arising from the 90-degree phase change. The method of solving for thickness using these equations is validated by the community.

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Homework Statement


A thin film of oil (n = 1.23) is located on a smooth, wet pavement. When viewed perpendicular to the pavement, the film reflects most strongly red light at 640 nm and reflects no light at 569 nm. How thick is the oil film?


Homework Equations


2nt=(m+.5)*(wavelength)------constructive interference
2nt=m* wavelength------------destructive interference
n=index of refraction
t= thickness
m= order number

The Attempt at a Solution


So I tried to set the two equations together and using the corresponding wavelengths to solve for m. Next I just plugged m into one of the equations and using the corresponding wavelength to find t. Is that the correct method of doing this problem?
 
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I believe you have the formulas for constructive and destructive interference reversed somewhat. They should be:

Constructive: 2nt = m\lambda

Destructive: 2nt = (m-1/2)\lambda
 
Hm I think they are the same thing. My textbook says it's that way, the only difference is the 90 degree phase change. But would be method be correct?
 
Yes, I guess they are both correct. Just in case you were wondering I looked up the formulas for thin films posted above in Knight's Physics book.(Not my favorite, but the only one I had on me.) Sorry for any confusion I may have caused.
 
Last edited:
np thanks for the verification
 

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