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Traced this down to an error in my formula as I'd copied it down; it's (sqrt(Voy^2 + 2gh)+Voy) / g, not (sqrt(Voy^2 + 2gh)-Voy) / g. Thanks though! [/color]
A 0.57 kg projectile is fired into the air from a cliff that's 13.9 m above a valley.
Initial velocity = 7.97 m/s
Angle: 51° above horizontal.
Acceleration = g
1: How long is the projectile in the air?
2: How far from the bottom of the cliff does the projectile land?
I tried to use (sqrt(Voy^2 + 2gh)-Voy) / g to find time after breaking down the initial velocity into axial components, but this yields 1.1669 s - obviously incorrect (and verified as such).
My shot at the first portion of this is above, since the equation was used in lecture as a way to find the time (in order to find the range) of an object fired at an angle from an elevated position. Just over one second doesn't check out logically, but I'm not sure why a given formula isn't yielding proper numbers.
Homework Statement
A 0.57 kg projectile is fired into the air from a cliff that's 13.9 m above a valley.
Initial velocity = 7.97 m/s
Angle: 51° above horizontal.
Acceleration = g
1: How long is the projectile in the air?
2: How far from the bottom of the cliff does the projectile land?
Homework Equations
I tried to use (sqrt(Voy^2 + 2gh)-Voy) / g to find time after breaking down the initial velocity into axial components, but this yields 1.1669 s - obviously incorrect (and verified as such).
The Attempt at a Solution
My shot at the first portion of this is above, since the equation was used in lecture as a way to find the time (in order to find the range) of an object fired at an angle from an elevated position. Just over one second doesn't check out logically, but I'm not sure why a given formula isn't yielding proper numbers.
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