Finding Total momentum of a system

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SUMMARY

The total momentum of a system consisting of a 2.2-kg cart moving at +4.3 m/s and a 1.0-kg cart at -1.1 m/s is calculated using the formula p=mv. The individual momenta are p1=9.46 kg·m/s and p2=-1.1 kg·m/s, resulting in a total momentum of 8.36 kg·m/s when summed. The user confirmed that the total momentum is indeed found by adding the individual momenta together.

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Homework Statement



A 2.2-kg cart is rolling along a frictionless, horizontal track towards a 1.0-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is +4.3 m/s, and the second cart's velocity is -1.1 m/s.*(a)*What is the total momentum of the system of the two carts at this instant?*(b)*What was the velocity of the first cart when the second cart was still at rest?

Homework Equations



p=mv

The Attempt at a Solution



So I found the momentums of each individual cart, (p1=9.5N and p2=-1.1N), do I just add the two values for the total momentum of the system? As in: 9.5N + -1.1N = 8.4 N

Thank you
 
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edit: nevermind, to find the total momentum yes you just them together
 
Last edited:
Thank you very much.
 

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