Momentum with Two Carts on a Low-Friction Track

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Homework Help Overview

The discussion revolves around a physics problem involving momentum and reference frames, specifically focusing on two carts on a low-friction track. The original poster presents a scenario where one cart is moving while the other is supposed to come to rest in the student's reference frame after a collision.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the conservation of momentum equation but expresses confusion regarding the correct velocities to use in different reference frames. Some participants question the mixing of reference frames in the calculations and suggest ensuring consistency in the chosen frame.

Discussion Status

Participants are actively engaging in clarifying the use of reference frames and the implications for the momentum calculations. There is an ongoing exploration of how to manipulate the momentum equation correctly, with some guidance offered on focusing on a single reference frame.

Contextual Notes

There is mention of specific velocities and conditions that need to be adhered to, such as the teacher's instruction to use a particular value for the velocity of cart 1 after the collision. The original poster also notes confusion regarding the results obtained from their calculations.

xxphysics
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Homework Statement


A student runs an experiment with two carts on a low-friction track. As measured in the Earth reference frame, cart 1 (m = 0.48 kg ) moves from left to right at 1.0 m/s as the student walks along next to it at the same velocity. Let the +x direction be to the right.

A. What velocity v⃗ E2,i in the Earth reference frame must cart 2 (m = 0.16 kg ) have before the collision if, in the student's reference frame, cart 2 comes to rest right after the collision and cart 1 travels from right to left at 0.33 m/s?
B. What does the student measure for the momentum of the two-cart system?
C. What does a person standing in the Earth reference frame measure for the momentum of each cart before the collision?

Homework Equations


(m1)(Ve1x,i) + (m2)(Ve2x,i) = (m1)(Ve1x,f) + (m2)(Ve2x,f)

The Attempt at a Solution


A. (0.48 kg)(1 m/s) + (0.16 kg)(Ve2x,i) = (0.48 kg)(-(1/3)m/s) + (0.16 kg)(0 m/s)
I got Ve2x,i = -2.0 m/s which doesn't make sense and it is in fact wrong. Where am I messing up? Also our teacher said to use (1/3) for the velocity of cart 1 after the collision instead of 0.33. I did try both, 0.33 gave me 3.99 which I entered as 4 and it was wrong.
 
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Check your frame of references. Your relationship is a mixture of velocities in the Earth frame and in the students frame. You must pick a frame and ensure all numbers are for that frame only.
 
rpthomps said:
Check your frame of references. Your relationship is a mixture of velocities in the Earth frame and in the students frame. You must pick a frame and ensure all numbers are for that frame only.
How do you manipulate the equation to do so? I'm sorry we've just started reference frames and I don't totally understand how to make sure the equation distinguishes from the two.
 
Well, the person is walking at 1 m/s and they notice that a cart is stationary after a collision. How fast must the cart be moving in the Earth's frame in order for the person to see this?
 
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