Finding Trigonometric Limits through Calculator Techniques

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Homework Help Overview

The problem involves finding the limit of a function defined as repeated applications of the cosine function, specifically f(x) = cos(x), for x = 100 radians and n approaching infinity. Participants are tasked with developing a calculator technique to compute f^n(x) for n from 1 to 20.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using a calculator to repeatedly apply the cosine function, while others propose developing a different formula or method. There are discussions about visualizing the process and identifying patterns in the outputs.

Discussion Status

The discussion is ongoing, with participants exploring the behavior of the function through graphical representation and repeated calculations. Some guidance has been offered regarding the concept of fixed points and how they relate to the limit being sought.

Contextual Notes

Participants are working under the constraints of using a calculator and are exploring the implications of repeated function applications without a formal method established. There is mention of needing to achieve accuracy to seven decimal places.

lightningz
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Homework Statement


Let f(x)=cos (x). Denote f^2(x) = ff(x), f^3(x)=fff(x) and so on.
For x=100 radians, find f^n(x) for n=1 to 20
Develop a calculator technique to find f^n(x) for any given value of n. Hence, find correct to 7 decimal places, the limit of f^n(x) for x= 100 radians and n approaching infinity.



Homework Equations




The Attempt at a Solution


sorry,i have no idea how to tackle this question.can any1 help me?=)
 
Last edited:
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Any vague ideas? The problem just asks for a 'calculator technique'. I would just set my calculator for radian mode, put in 100 and then just keep pushing 'cos', 'cos', 'cos'...
 
oh yeah...i tot we need to develop another different formula or method to calculate the value rather than using the calculator and cos cos cos.
 
hi lightningz

so use the caclulator to see what happens with repeated applications, then see if you can work out why...

conceptually, you could imgine the process as taking:
x1 point = 100radians, y1 = cos(x 1)

then transfer that back to the x-axis using the line y = x, so x2 = y1 = cosx, now repeat the process
y2 = cos(x 2)= cos(cos(x 1))

try drawing it out for a few cycles (after the first it will be near the y axis)
is there any pattern you can see? can you describe it?
 
the graph become smaller and smaller(ie converging to a certain value) and when n=infinty, it actually becomes a straight line. in this case, limit of cos^n(x),(x--->infinity), for all value of x is that particular value..that's what i got...urm..is that what the question want?=)
 
which graph?

i assume you are plotting:
[tex]f^n(100) = Cos(f^{n-1}(100))[/tex] against n

did you try what i mentioned? plot the line f(x) = cos(x) and g(x) = x and trace the operation of the function by moving a point between those 2 lines, this should illuminate what is going on

based on your question its probably enough to hit cos on your calculator enough times that the numbers down to the seventh decimal stop changing... probably about 40 or so times (easier in a speadhseet)

though there is a bit more going on here - have you heard of a fixed point of a function before?
 
sorry.i never heard of fixed point.
well the intersection point of the two graphs f(x)= cos (x) and g(x)=x..i got it by plotting in my calculator..which is the value for limit of cos^n(x),(x--->infinity), is that point called fixed point? thanks a lot for helping all the time =)
 
fixed point of a function where f(x) = x, so repeated application of the function does not cahneg the value at the fixed point

have a look here, it actually has a picture of f(x) = cos(x) as I was trying to explain
http://en.wikipedia.org/wiki/Fixed_point_(mathematics )
 
Last edited by a moderator:
thanks.i think i understood already =) such a nice guy you are..:wink:
 

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