- #1
laura_a
- 66
- 0
Homework Statement
I need to find the solution to the d.e y''=1 with initial conditions y(0)=y'(0)=0
I have the formula to use
[tex] Y(x) = y_2(x) \int \frac{y_1}{W(t)} g(t)dt - y_1(x) \int \frac{y_2}{W(t)}g(t)dt [/tex]
And I've worked out easily that one solution is [tex] \frac{x^2}{2} [/tex]
I just tried to use the formula I've got to find another solution y_2 but I ended up getting the same as I've got for y_1.
Is there an easier way to find a solution. The first part of the question asked to find 2 solutions to the d.e y''=0 and I found them to be y_1=1 and y_2=x, it says I can use this information to solve the d.e y''=1 but I don't see how?
Can anyone lead me in the right direction? :) Thanks