Finding Value of k for Tangent to y=\frac{3x}{\sqrt{1+x}} at x=3

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SUMMARY

The discussion focuses on finding the value of k in the equation of the tangent line 15x - 16y = k to the curve defined by y = \frac{3x}{\sqrt{1+x}} at the point where x = 3. The solution involves calculating the y-coordinate of the curve at x = 3, determining the slope of the curve at that point, and equating it to the slope of the tangent line. The final value of k is derived through these calculations, confirming the relationship between the curve and its tangent line.

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Homework Statement


The equation of a curve is y=[tex]\frac{3x}{\sqrt{1+x}}[/tex].
Given that the equation of the tangent to the curve at the point x=3 us 15x-16y=k , find the value of k. SOLVED

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The Attempt at a Solution

 
Last edited:
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Do you know the y-coordinate on the curve when x = 3?
Do you know how to find the slope of a curve (i.e., the slope of the tangent line to the curve)?
Do you know how to find the slope of the line 15x - 16y = k?
 

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