Finding value of unknown charge

  • Thread starter Thread starter member 731016
  • Start date Start date
  • Tags Tags
    Charge Value
Click For Summary
The discussion centers on the direction of the electric field produced by an unknown charge, q, at the origin. It clarifies that if q is positive, the electric field points to the left, while if q is negative, the field points to the right, as a positive test charge would be attracted to the negative charge. The assumption that the electric field is always to the left is incorrect; the direction depends on the sign of q. The participants emphasize understanding the relationship between charge polarity and electric field direction. This highlights the importance of analyzing charge characteristics in physics problems.
member 731016
Homework Statement
Please see below
Relevant Equations
Please see below
For this problem,
1674021666843.png

The solution is,
1674021637296.png

However, why did they assume that the electric field produced by charge q is always pointing to the left at the origin?

Many thanks!
 
Physics news on Phys.org
Callumnc1 said:
Homework Statement:: Please see below
Relevant Equations:: Please see below

For this problem,
View attachment 320613
The solution is,
View attachment 320612
However, why did they assume that the electric field produced by charge q is always pointing to the left at the origin?

Many thanks!
They are not assuming that the electric field is pointing to the left.

Think about it.

If ##q## is a positive charge, then indeed, the electric field at the origin, due to ##q##, is to the left (negative).

What if ##q## is negative? Then you have a negative number multiplied by a negative number. In what direction is the electric field, due to ##q##, pointing in this case?
 
Last edited:
  • Like
Likes member 731016
SammyS said:
They are not assuming that the electric field is pointing to the left.

Think about it.

If ##q## is a positive charge, then indeed, the electric field at the origin, due to ##q##, is to the left (negative).

What if ##q## is negative? Then you have a negative number multiplied by a negative number. In what direction is the electric field, due to ##q##, pointing in this case?
Thank you for your reply @SammyS !

If ##q## is negative, then the electric field due to the charge will be pointing to the right as a positive test charge would be attracted to the negative charge.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 19 ·
Replies
19
Views
1K
Replies
21
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
6
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
912
  • · Replies 10 ·
Replies
10
Views
915
  • · Replies 11 ·
Replies
11
Views
2K