Finding values that make a determinate = 0

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Homework Help Overview

The problem involves finding values of the variable 'a' in a 3x3 matrix that make the determinant equal to zero. The matrix is defined with specific elements, and the context is rooted in linear algebra.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the determinant using the Cofactor theorem and arrives at a polynomial equation. Some participants question the accuracy of the polynomial's constant term, while others suggest trusting the mathematical output from computational tools.

Discussion Status

The discussion is ongoing, with participants exploring the correctness of the determinant calculation and the nature of the roots. There is a recognition of differing expectations regarding the nature of the roots (integer vs. non-integer).

Contextual Notes

There is an implied constraint regarding the expectation of integer solutions, which may influence the participants' interpretations of the results.

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Homework Statement



Given the matrix A = {a, 3, 8}{a, -3, 4}{7, -4, a} find all values of a that make det(A) = 0.

(each {} is a row in the matrix, 3x3)

The Attempt at a Solution



I've expanded it out using the Cofactor theorem, ie. a11c11 + a21c21 + a31c31, and I come out with a polynomial, -2(3a^2+8a-126) which I equate to 0. Solving for the quadratic gives ugly roots which I can't see being correct.

Thanks for any help
 
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Doing a very quick calculation, are you sure your '-126' shouldn't be '126'? (When you factor out the -2, shouldn't you have a positive 126 left?)
 
Well according to maple your determinant is correct. You should really trust the math instead of your intuition about what you can see being correct.
 
Huh, it was correct :P I just figured the answer would be integers. Thanks for the help :)
 

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