Finding velocity given radius and acceleration

Click For Summary
SUMMARY

The discussion centers on calculating the velocity of a car traveling over a hump with a radius of 20 meters, given a net acceleration of 3.8 m/s². The formula used is derived from centripetal acceleration, specifically a = v²/r, leading to the calculation v = √(ar). The correct velocity calculated is approximately 8.718 m/s. Additionally, there is a query regarding the felt acceleration on a flat road, indicating a need for clarification on interpreting forces experienced by occupants.

PREREQUISITES
  • Centripetal acceleration concepts
  • Basic algebra for solving equations
  • Understanding of forces and motion
  • Familiarity with the formula v = √(ar)
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Explore the relationship between net acceleration and forces in motion
  • Learn about the effects of different road conditions on vehicle dynamics
  • Investigate advanced topics in kinematics and dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to motion and forces.

KLI897
Messages
3
Reaction score
0

Homework Statement


A car travels over a hump in the road of radius 20 meters. How fast is the car traveling if the occupants feel a net acceleration of 3.8 m/s2

Homework Equations


a = v2/r
v = √ar

The Attempt at a Solution


I did this but according to my teacher this isn't correct.
v = √(3.8 m/s2)(20 m)
v = 8.718 m/s
 
Physics news on Phys.org
KLI897 said:

Homework Statement


A car travels over a hump in the road of radius 20 meters. How fast is the car traveling if the occupants feel a net acceleration of 3.8 m/s2

Homework Equations


a = v2/r
v = √ar

The Attempt at a Solution


I did this but according to my teacher this isn't correct.
v = √(3.8 m/s2)(20 m)
v = 8.718 m/s
What acceleration would the occupants feel on a flat road? I agree it is not completely clear, but I would guess you are to interpret the felt acceleration in terms of the forces felt.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
5K