Finding velocity of car in Carnival ride

  • Thread starter Thread starter chicagobears34
  • Start date Start date
  • Tags Tags
    Car Velocity
Click For Summary
SUMMARY

The discussion focuses on calculating the velocity of cars on a carnival ride called The Rocket, which features a disk with a diameter of 6 meters and chains that extend 6 meters. The cars swing out at a 30-degree angle from vertical, complicating the radius calculation. The correct formula for velocity is derived from the centripetal force equation, Fc=m(v^2)/r, and the gravitational force, w=mg. The participants emphasize the importance of accurately determining the radius of the circular path, which involves understanding the geometry of a 30-60-90 triangle.

PREREQUISITES
  • Understanding of centripetal force and gravitational force equations
  • Knowledge of trigonometric functions, particularly in 30-60-90 triangles
  • Ability to visualize and draw geometric relationships in physics problems
  • Familiarity with basic kinematics and dynamics concepts
NEXT STEPS
  • Review the derivation of centripetal force equations in physics
  • Study the properties and applications of 30-60-90 triangles in problem-solving
  • Practice drawing and analyzing free-body diagrams for complex motion scenarios
  • Explore the relationship between angular velocity and linear velocity in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples to illustrate these concepts.

chicagobears34
Messages
37
Reaction score
0

Homework Statement


You've taken your neighbor's young child to the carnival to ride the rides. She wants to ride The Rocket. Eight rocket-shaped cars hang by chains from the outside edge of a large steel disk. A vertical axle through the center of the ride turns the disk, causing the cars to revolve in a circle. You've just finished taking physics, so you decide to figure out the speed of the cars while you wait. You estimate that the disk is 6m in diameter and the chains are 6m long. The ride takes 10s to reach full speed, then the cars swing out until the chains are 30degrees from vertical.


Homework Equations


Fc=m(v^2)/r
w=mg

The Attempt at a Solution


I summed the Forces in the Y direction, so 0=Ft*cos30 -mg
Ft being the tension force on the cable of the car
Ft=mg/cos30
2nd equation: Ft*sin30 -Fc
Fc=Ft*sin30
sub in mv^2/r for Fc
solved for v and i got v=sqrt(r*g*tan30)
i plugged in the radius of the disk which is 3m and gravity which is 9.81m/s^2
v=4.122m/s^2, but that was wrong
What am I doing wrong?
 
Physics news on Phys.org
The radius of the cars circle is not the same as the disc radius.
 
chicagobears34 said:
solved for v and i got v=sqrt(r*g*tan30)
i plugged in the radius of the disk which is 3m and gravity which is 9.81m/s^2

Careful. Are you sure r is the radius of the disk?
 
if I do radius as 9m then I get 7.14m/s as the velocity, which is wrong also
 
You are not calculating the radius correctly. Recheck your geometry and trig for the swing angle
 
PhanthomJay said:
You are not calculating the radius correctly. Recheck your geometry and trig for the swing angle

ok how would I go about calculating it properly, I have no idea
 
Draw a side view of the disk. Draw the car hanging vertically (before the ride starts). On the same figure draw the car hanging from the same point at 30 degrees from the vertical (after the ride starts). Draw a line representing the radius of the circle that the car is traveling in. Can you see how to determine the value of the radius?
 
well doesn't it make a 30 60 90 triangle?
so the radius would be 3+(2*9/root3)?
 
chicagobears34 said:
well doesn't it make a 30 60 90 triangle?
Yes.
so the radius would be 3+(2*9/root3)?
The expression in the parentheses is incorrect. Which side of the 30 60 90 triangle represents the additional amount you need to add to the 3 m radius of the disk? What is the length of the hypotenuse of the triangle?
 
  • #10
the hypotenuse would be the length i need to add by 3. so it should be 3+(2*6/root3)
because the side opposite of the 60 degree angle is a*root3 and the hypotenuse is 2a.
 
  • #11
Is your diagram similar to the attached figure? If so, what is the length of the hypotenuse of the triangle a b c?
 

Attachments

  • Rotating Ride.jpg
    Rotating Ride.jpg
    5.8 KB · Views: 657

Similar threads

Replies
8
Views
2K
Replies
27
Views
4K
Replies
4
Views
4K
Replies
7
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 9 ·
Replies
9
Views
12K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
16K
  • · Replies 2 ·
Replies
2
Views
7K
Replies
12
Views
3K