Finding Vertical and Horizontal Forces on a Hinged Bar

[MozAngeles]

Homework Statement

End A of the bar AB in the figure rests on a frictionless horizontal surface, and end B is hinged. A horizontal force F of magnitude 103 N is exerted on end A. You can ignore the weight of the bar.

A.)What is the horizontal component of the force exerted by the bar on the hinge at B?
B.)What is the vertical component of the force exerted by the bar on the hinge at B?

Homework Equations

for part A.) is 103 because the summation of the forces in the x direction is equal to zero and all you have in the x direction is the force applied and negative force horizontal. So for part B.) the summation of the forces on the y-axis i thought it was just force vertical equal to zero but, well it needs something else. i just don't know what!

The Attempt at a Solution

above is my attepmt i know it is not right. I also am confused by the summation for torque because it says the bar is wiethless. so yeah justa steer in the right direction would be nice thanks.

 

[rl.bhat]

Let the bar makes angle θ with the horizontal surface.
Resolve the force F into two components.
1) F*cosθ along the bar
2) F*sinθ perpendicular to the bar which balances the normal reaction.
Now resolve F*cosθ at the hinges.

 

[Femme_physics]

It would help if you (try to) make a free body diagram first. Can I see it?

 

[MozAngeles]

So For the vertical would it be the force times sin $$\theta$$?

 

[Femme_physics]

Good.

But a free body diagram should mark down all the forces, you only have F. What other forces do you have that can draw?

So For the vertical would it be the force times sin

I don't really know what you mean.

But for the sum of all forces on y, all you have is By and Na. By being the vertical component of hinge B, and Na being the normal force that the ground is acting on the bar. Since these are the only two forces, they must equal each other, as per

Na - By = 0

But, you'll get there. Start first by marking all the vectors.