Finding Vmax of a Block in SHM: Mass, Spring Constant, and Distance

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Homework Help Overview

The problem involves a block attached to a spring, exploring the maximum velocity of the block when displaced from its equilibrium position. The context is simple harmonic motion (SHM), with parameters including mass, spring constant, and displacement.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods to find the maximum velocity, including oscillation formulas and the work-energy theorem. There is confusion regarding the correct application of formulas and the significance of amplitude.

Discussion Status

Some participants have offered guidance on using oscillation formulas and the work-energy theorem. There is an ongoing exploration of different approaches, with no explicit consensus reached on the method to be used.

Contextual Notes

Participants note the importance of unit consistency and the correct interpretation of variables in the formulas being discussed. There is also mention of a multiple-choice format for the question, which may influence the approach taken.

Litdaze

Homework Statement


A block with mass m=200g is attached to a spring with a elastic constant of k=5.0 N/m.
The block is pushed at a distance x=5.00cm of its equilibrium position, in a surface with no friction.
Then its dropped of that position. Assume for t=0s that the block is at rest.
What is the maximum velocity of the block?
3a1cb6fe8d8e320aa4a4bf6382213e13.png

This is a multiple choice question, solutions being
a) 0.250 m/s
b) 1.25 m/s
c) 0.05 m/s
d) 5.0 m/s

Homework Equations


N/A

The Attempt at a Solution


bb927676ea389d454c9ec6b4ae65d102.png

I can't figure how to find Vmax[/B]
 
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ok, that is Time Period and/or angular frequency ... do you want to use Hooke's Law (PE into KE), or do you want to use oscillation formulas?
 
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Oscillations I guess, I really can't figure out how to find Vmax. I've tried the Vmax=Aw but somehow it resulted in 1, which isn't the answer.

Vmax = Aw = (0.2 kg)(5 rad/s) = 1.

I'm really confused
 
in oscillations, capital A is the oscillation Amplitude (not the mass)
You need to keep track of your UNITS !
 
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Ok then so Vmax = Aw = (0.05)(5) = 0.250 m/s?

It makes sense now.
 
I think you can simply use the work energy theorem here.
 

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