Finding Wavelength of mosquito wings

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    Wavelength Wings
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Discussion Overview

The discussion revolves around calculating the wavelength of sound produced by a mosquito flapping its wings at a frequency of 600 Hz. Participants explore the relationship between frequency, speed of sound, and wavelength, focusing on the mathematical approach to find the wavelength.

Discussion Character

  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant asks how to find the wavelength of the sound produced by a mosquito, given its wingbeat frequency of 600 Hz.
  • Another participant suggests using the formula L = V/600, where V is the speed of sound.
  • A participant provides the formula v = f/λ, indicating the relationship between wave speed, frequency, and wavelength.
  • There is confusion expressed about rearranging the equation to solve for wavelength after substituting values.
  • One participant proposes a wavelength of 0.6 meters based on their calculations.
  • Another participant confirms the calculation of wavelength using λ = v/f, substituting the speed of sound as 344 m/s and frequency as 600 Hz.
  • Participants express appreciation for the assistance provided in the discussion.

Areas of Agreement / Disagreement

There is no clear consensus on the final value of the wavelength, as one participant suggests 0.6 meters, while others are engaged in calculations and discussions about the rearrangement of equations.

Contextual Notes

Some participants express confusion regarding the rearrangement of equations and the application of the formulas, indicating potential gaps in understanding the mathematical steps involved.

zachcumer
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How do you find the wavelength of this: A mosquito flaps its wings 600 vibrations per second ( it is this motion that produces the annoying 600-Hz buzz). How far does the sound travel between wing beats? In other words, find the wavelength of the mosquito’s sound.

Thanks
 
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Look up the speed of sound V. Then L=V/600.
 
[tex]v=frac{f}{lambda}[/tex]
 
Last edited:
so is the wave length...

so I substituted and got 344=600*(n)...how do I do the rest confused...how do I rearrange the equation?
 
oh its .6 meters right?
 
oh

oh its .6 meters right?
 
[tex]\lambda = \frac{v}{f}[/tex]

So...

[tex]\lambda= \frac{344}{600}[/tex]
 
Thanks Very Helpful!
 
Good to hear.
 

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