Finding where a ball lands on a slope given initial velocity

[jjiimmyy101]

What do you do to find the x and y coordinates of a ball that is thrown from a building onto a slope?

*Initial velocity is given along with the angle
*The height of the building is given
*And the angle of the sloped ground is given

 

[Poobel]

You should at least try and solve the problem since this place is for help not just asking physisists to solve the problems for you.

Word of advice (sorry for offtop) read sticky notes

No hard feelings

 

[jjiimmyy101]

Equations:
Horizontal Component (a=0): v =vo + a*t; x =xo + vo*t +0.5*a*t^2; v^2=vo^2 + 2*a*(s-so)

Vertical component (a=-9.81): v=vo + a*t; y=yo + vo*t + 0.5*a*t^2; v^2= vo^2 + 2*a*(y-yo)

*(vo)x=12
*(vo)y=16
*t=?
*...

 

[Poobel]

try using

d=Vit+1/2a(t)^2

If your Vi is zero it can work out nicely if you find acceleration

to find acceleration use

Vf^2=Vi^2+2ad work it back assuming you know Vf, Vi and displacement

 

[jjiimmyy101]

I should have been more specific.

Problem: The ball is thrown from the tower with a velocity of 20m/s. Determine the x and y coordinates to where the ball strikes the slope. Also, find the speed at which the ball hits the ground.

**Picture attached

 

[Poobel]

The second part is really easy knowing your initial velocity and displacement you should be able to find your final velocity

use Vf^2=Vi^2+2ad where a is acceleration due to Earth's gravity and d is your displacement i.e. distance to the ground

first part with the slope though I just simply don't understand -- picture would help a lot

 

[himanshu121]

u need to know the slope

 

[jjiimmyy101]

The picture is in the post above.

"Determine the x and y coordinates to where the ball strikes the slope."

The ball doesn't land on a flat surface. The ground is raised by an angle of 26(degrees) to the horizontal.

I hope that clears it up alittle better.