Block launching off ramp given initial velocity and Friction

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physicN00Bz
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Homework Statement



a block is at the base of a ramp of angle 35degrees. The ramp is 5 m long and has a coefficient of static and kinetic friction of .6 and .2 respectively. The block is initially given a velocity of 12 m/s up the ramp, how far from the ramp will the block land?

my main problem is finding the final velocity as the block exit the ramp, honestly i really don't know where to start.

Homework Equations


to find the final velocity of the block exiting the ramp i use

0.5 * m * v^2 = m * h * g + m * g * cos (theta) * Kf * L + 0.5 * m * V^2


The Attempt at a Solution



The answer is 9.75 m, all of my answer come out to be 8.57m or something close, what am i doing wrong? how do i applied the static friction into the equation?
 
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physicN00Bz said:
to find the final velocity of the block exiting the ramp i use

0.5 * m * v^2 = m * h * g + m * g * cos (theta) * Kf * L + 0.5 * m * V^2

This equation gives the final speed the block leaves the ramp. How do you proceed to get the the distance from the ramp the block will land?

ehild