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## Homework Statement

A point charge of -1.0 µC is located at the origin. A second point charge of 16 µC is at

*x*= 1 m,

*y*= 0.5 m. Find the

*x*and

*y*coordinates of the position at which an electron would be in equilibrium.

## Homework Equations

F=k((q1q2)/r^2)

## The Attempt at a Solution

I have gotten pretty far with the problem, but I have reached a block. I used the equation F=k((q1q2)/r^2) for both the point at the origin(F1) and the point at (1,0.5) (F2).

I have come up with the equations:

F1=k(-1μC)/(r_2)^2

F2=k(16μC)/(r_2)^2

Then I set them equal to each other:

((-1μC)/(r_1)^2)=((16μC)/(r_2)^2)

I know from here I should find a way to substitute r_2 to put it in terms of r_1 but I'm not sure how to go about it. I drew out where the points would be graphically, and I put the first point at the origin and the second point at (1,0.5), is that where I went wrong? Any help would be appreciated.

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