Finding Work given mass and distance

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To calculate the work required to lift a 4.0 kg concrete block to a height of 2.0 m, the force is determined using F = mg, resulting in 39.2 N. Applying the work formula W = Fd gives a total work of 78.4 J. Concerns arise when comparing this calculation to a similar problem involving a 5.0 kg bag of sugar, where the provided answer of 3.22 J seems inconsistent with the calculations performed. The discrepancy suggests that the book's answer may be incorrect, as the calculations for both scenarios are based on the same principles. Overall, the calculations for lifting the concrete block appear to be accurate.
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Homework Statement


How much work is required to lift a 4.0 kg concreted block to a height of 2.0 m?

mass = 4.0 kg
distance = 2.0 m


Homework Equations



W = Fd
F = mg (not sure if this is used)

The Attempt at a Solution



To find Force, I used the formula F(orce) = m(***) times g(ravity) which would be F=(4.0kg)(9.8m/s2), giving me F=39.2N
Now, I used this information in the W = Fd equation, giving me W = (39.2N)(2.0m) = 78.4 J

The reason I am unsure if this is correct is that an example is given with a very similar problem:
m=5.0kg
d=0.45m (above the counter)

The answer given is 3.22 J. Using the formulas I used, I come up with 22.05 J.
 
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Your answer looks OK...is the 'similar' problem exactly similar??
 
It is exactly similar. The wording is this:

A 5.0 "kilo" bag of sugar is on a counter. How much work is required to put the bag on a shelf a distance of 0.45m above the counter?

The answer given is 3.22 J

That really made me think my answer is wrong, but I suppose the book could be wrong - I wanted to run it by some experts to be sure.
 
That's a hefty bag of sugar, must be for a restaurant chain since it's about twice the weight of what I buy in the supermarket. Or maybe its from BJ's or one of those wholesale outfits where sizes are double or triple or more the supermarket size.:wink: Anyway, their answer doesn't make sense. Welcome to PF!:smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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