Finding Work given mass and distance

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SUMMARY

The discussion centers on calculating the work required to lift a 4.0 kg concrete block to a height of 2.0 m, resulting in a work value of 78.4 J using the formula W = Fd, where F is the force calculated as F = mg (39.2 N). The participant expresses confusion regarding a similar problem involving a 5.0 kg bag of sugar, which yields a different work value of 3.22 J, despite using the same formulas. The discrepancy raises questions about the accuracy of the provided answer for the sugar bag problem.

PREREQUISITES
  • Understanding of Newton's second law of motion (F = ma)
  • Knowledge of gravitational acceleration (g = 9.8 m/s²)
  • Familiarity with the work-energy principle (W = Fd)
  • Basic algebra for solving equations
NEXT STEPS
  • Review the concept of gravitational potential energy and its relation to work
  • Explore the implications of mass and distance on work calculations
  • Investigate common errors in physics problem-solving, particularly in work-energy problems
  • Practice with additional examples of work calculations involving varying masses and distances
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding work calculations in physical systems.

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Homework Statement


How much work is required to lift a 4.0 kg concreted block to a height of 2.0 m?

mass = 4.0 kg
distance = 2.0 m


Homework Equations



W = Fd
F = mg (not sure if this is used)

The Attempt at a Solution



To find Force, I used the formula F(orce) = m(***) times g(ravity) which would be F=(4.0kg)(9.8m/s2), giving me F=39.2N
Now, I used this information in the W = Fd equation, giving me W = (39.2N)(2.0m) = 78.4 J

The reason I am unsure if this is correct is that an example is given with a very similar problem:
m=5.0kg
d=0.45m (above the counter)

The answer given is 3.22 J. Using the formulas I used, I come up with 22.05 J.
 
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Your answer looks OK...is the 'similar' problem exactly similar??
 
It is exactly similar. The wording is this:

A 5.0 "kilo" bag of sugar is on a counter. How much work is required to put the bag on a shelf a distance of 0.45m above the counter?

The answer given is 3.22 J

That really made me think my answer is wrong, but I suppose the book could be wrong - I wanted to run it by some experts to be sure.
 
That's a hefty bag of sugar, must be for a restaurant chain since it's about twice the weight of what I buy in the supermarket. Or maybe its from BJ's or one of those wholesale outfits where sizes are double or triple or more the supermarket size.:wink: Anyway, their answer doesn't make sense. Welcome to PF!:smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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