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In a paper I have

[tex]v_{n,k} = \Delta^K ( (-1)^n n^k y_n )[/tex]

with [tex]n = K, \dots , N-1[/tex], [tex]k = 0, \dots, K[/tex] and [tex]N = 2K[/tex]

where [tex]\Delta^K[/tex] is the Kth finite difference operator.

As you can see, all [tex]v_{n,k}[/tex] consistute an [tex](N-K) \times (K+1)[/tex] matrix.

So without the [tex]\Delta[/tex]'s, each [tex]v_{n,k}[/tex] would be a scalar. I do not see how to calculate the finite difference of a scalar?!

Well, probably it is not a finite difference. But can anybody tell me what could be meant with that?

Regards,

divB

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# Finite differences on scalar? Matrix?

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