What is the Finite Field Order of Z[i]/A in Z[i] with A=<1+i>?

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SUMMARY

The discussion centers on determining the finite field order of Z[i]/A where A=<1+i> in Z[i]. It is established that Z[i]/A is indeed a finite field. The order of this field can be calculated by recognizing that the ideal generated by A corresponds to the norm of the generator, which is 2. Therefore, the order of the finite field Z[i]/A is 2.

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  • Understanding of Gaussian integers (Z[i])
  • Knowledge of ideals in ring theory
  • Familiarity with field theory and finite fields
  • Basic concepts of norms in algebraic structures
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Homework Statement



If A=<1+i> in Z, show that Z/A is a finite field and find its order

Homework Equations





The Attempt at a Solution



Not sure where to start...

Z/A = {m+ni + A, m, n integers} ? is that right?

And I don't know what else to do.
 
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Maybe you can use that 2=(1+i)(1-i)...
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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