First-Order Circuit Transient Response Question that i with

Click For Summary
SUMMARY

The discussion focuses on calculating the transient response of a first-order circuit after a switch operation. The user seeks to determine the current (Ix) and voltage (Vx) at specific times (75 µs and 190 µs) after the switch closes and then reopens. Key calculations include the voltage across the capacitor at 105 µs, which is 7.1467V, and the time constant (tau2) calculated as 33nF multiplied by 3900 ohms. The user is advised to find the Thevenin equivalent of the circuit to simplify the analysis for subsequent calculations.

PREREQUISITES
  • Understanding of first-order circuit analysis
  • Knowledge of Thevenin's theorem
  • Familiarity with time constants in RC circuits
  • Ability to perform exponential decay calculations
NEXT STEPS
  • Calculate the Thevenin equivalent circuit for the given network
  • Learn about the impact of different resistances on time constants in RC circuits
  • Explore the derivation of voltage and current equations in first-order circuits
  • Study the effects of capacitor discharge in transient analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing transient responses in first-order circuits.

spoonjabba
Messages
7
Reaction score
0
The switch in the diagram below has been open for a long time prior to t = 0; then it closes at t = 0 and opens again at t = 105 µs. Find:

1. Ix(75 µs),
2. Vx(75 µs),
3. Ix(190 µs),
4. Vx(190 µs).

Attached is the diagram of the circuit and its answers.

so i understand how to get questions 1 and 2, but for 3 and 4 I am stuck.

i found the voltage of the capacitor at time 105µs so I am assuming I use that voltage as the initial condition to questions 3 and 4. I also know that the time constant(tau2) will be different as it will only be the C and R1.

these are the values i am calculating thus far.
vx(105us) = 7.1467V
Tau2 = 33n*3900
vx(190us) = 7.1467e^(-190us/tau2) << i have a feeling i have done something wrong here

thanks guys!
 

Attachments

  • 7.4.png
    7.4.png
    11.9 KB · Views: 548
Last edited:
Physics news on Phys.org
spoonjabba said:
The switch in the diagram below has been open for a long time prior to t = 0; then it closes at t = 0 and opens again at t = 105 µs. Find:

1. Ix(75 µs),
2. Vx(75 µs),
3. Ix(190 µs),
4. Vx(190 µs).

Attached is the diagram of the circuit and its answers.

so i understand how to get questions 1 and 2, but for 3 and 4 I am stuck.

i found the voltage of the capacitor at time 105µs so I am assuming I use that voltage as the initial condition to questions 3 and 4. I also know that the time constant(tau2) will be different as it will only be the C and R1.

these are the values i am calculating thus far.
vx(105us) = 7.1467V
Tau2 = 33n*3900
vx(190us) = 7.1467e^(-190us/tau2) << i have a feeling i have done something wrong here

thanks guys!
Hi spoonjabba, Welcome to Physics Forums.

The time constant ##\tau## will depend upon both of the resistances. I suggest that you "remove" the capacitor from the circuit and find the Thevenin equivalent of the remaining network (resistors and voltage supply). This will be the equivalent circuit that the capacitor will "see", and will consist of a single resistance in series with a voltage supply. It will then be a trivial matter to calculate the effective time constant and other values.
 

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
8K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K