First Order DE Problem: Self-Teaching Derivatives

[snowJT]

I've been kind of self teaching myself first order derivities...

this is really my first shot at it.. want to know if this is right so far

$$\frac{dy}{dx} = \frac{y(1-x^5y)}{x}$$

$$xdx = y (1-x^5y)dx$$

$$xdy = (1y-x^5y^2)dx$$

$$xdy = ydx - x^5y^2dx$$

$$\frac {xdy - ydx}{y^2} = \wr -x^5dx$$

$$\wr d\frac{x}{y} = \wr -x^5dx$$

$$\frac{x}{y} = \frac{-x^6}{6}$$

$$\frac{1}{y} = \frac{-x^7}{6}$$

does this look right so far? and how can I simplify it more?

 

[theperthvan]

you can check by substituting your answer back into the original eq'n

 

[dextercioby]

$$\frac{x}{y} = \frac{-x^6}{6}$$

$$\frac{1}{y} = \frac{-x^7}{6}$$

does this look right so far? and how can I simplify it more?

Check this part again. And put in some integration constant.

Daniel.