- #1
James889
- 192
- 1
Hi,
I tried to solve this by using the integrating factor technique
[tex]\begin{cases}
dy/dt +10y = 1 \\
y(1/10) = 2/10
\end{cases}[/tex]
So [tex]p(x) = 10t \rightarrow e^{10t}[/tex]
[tex]e^{10t} \cdot \frac{dy}{dt} + e^{10t} \cdot 10y = e^{10t}[/tex]
This part is confusing to me, i have two different variables y and t.
How do i integrate the left side?
I tried to solve this by using the integrating factor technique
[tex]\begin{cases}
dy/dt +10y = 1 \\
y(1/10) = 2/10
\end{cases}[/tex]
So [tex]p(x) = 10t \rightarrow e^{10t}[/tex]
[tex]e^{10t} \cdot \frac{dy}{dt} + e^{10t} \cdot 10y = e^{10t}[/tex]
This part is confusing to me, i have two different variables y and t.
How do i integrate the left side?