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I tried to solve this by using the integrating factor technique

[tex]\begin{cases}

dy/dt +10y = 1 \\

y(1/10) = 2/10

\end{cases}[/tex]

So [tex]p(x) = 10t \rightarrow e^{10t}[/tex]

[tex]e^{10t} \cdot \frac{dy}{dt} + e^{10t} \cdot 10y = e^{10t}[/tex]

This part is confusing to me, i have two different variables y and t.

How do i integrate the left side?

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# First order DE, using integrating factor

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