Flipping a coin (similar to the ballot problem)

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Homework Help Overview

The problem involves flipping a coin n times with a probability p of landing heads. The central question is to determine the probability that the number of heads is always greater than the number of tails throughout the sequence of flips.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various sequences of heads and tails for small values of n, questioning the completeness of possibilities. There is a discussion about defining a recursive function to count valid sequences and the challenges in deriving a summation for the results. Some participants suggest considering the problem in terms of probability distributions.

Discussion Status

The discussion is ongoing, with participants sharing their attempts at defining recursive relationships and expressing uncertainty about how to sum the results effectively. Some guidance has been offered regarding the mathematical formulation of the problem, but no consensus has been reached on a solution.

Contextual Notes

Participants are grappling with the constraints of the problem, including the requirement that heads must always outnumber tails at every flip. There is also mention of potential limitations in the initial approaches taken to solve the problem.

Random Variable
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Homework Statement



You flip a coin n times. The probability of getting a head on any flip is p. What is the probability that the number of heads flipped is always greater than the number of tails flipped?

The Attempt at a Solution



For example,

if n=1, the only possibility is H
if n=2, the only possibility is HH
if n=3, the two possibilities are HHH or HHT
if n=4, the three possibilites are HHHH, HHHT, or HHTH
if n=5, the six possibilites are HHHHH, HHHHT, HHHTT, HHHTH, HHTHH, and HHTHT

Of course you could keep doing this until you notice a pattern, take a guess at the formula, and then try to prove that forumula by induction. (I tried that approach but didn't get anywhere). Conditioning on the first flip clearly won't simplify the problem, and conditioning on the (n-1) flip or the nth flip doesn't seem to simplify matters either. I'm stumped.
 
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There's more possibility to n=3 and n=4 isn't it?


HHH, HHT, HTH, THH?
 
SiYuan said:
There's more possibility to n=3 and n=4 isn't it?


HHH, HHT, HTH, THH?

No. After every flip the total number of heads flipped up to that point must be greater than the number of tails flipped up to that point.
 
I'll tell you where I am so far. Let H(n,k) be the number of good sequences of length n (where heads lead all the time) and k is number of heads-number of tails. You can just define H(n,k)=0 if k>n or k<=0. Ok, so far? Write a recursion relation for H(n+1,k) in terms of H(n,...). That's easy. Now take the whole list [H(n,n),H(n,n-1)...H(n,1)] and figure out how to use it to construct the list [H(n+1,n+1),H(n+1,n),...,H(n+1,1)]. It's pretty easy. You just take the original list, chop off a bit, add some zeros in two different ways and add them. That let's you write a really simple computer program to compute the H(n+1) list from the H(n) list. That's great. Now that you have a simple way to construct the recursion you sit back an wait for your intuition to kick and tell you how to sum the whole thing up. Unfortunately, I'm still waiting. Any good ideas?
 
Random Variable said:
You flip a coin n times. The probability of getting a head on any flip is p. What is the probability that the number of heads flipped is always greater than the number of tails flipped?

I would suggest writing the question in mathematical terms to see what you are missing.

HINT: What type of probability distribution is this?

CS
 

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