Why is ro = 0.2255 in fluid dynamics vortices?

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SUMMARY

The discussion centers on the calculation of the parameter ro, which is determined to be 0.2255 in the context of fluid dynamics vortices. The problem involves a closed cylindrical tank containing water, rotated at an angular velocity of 40 rad/s. Participants reference Bernoulli's equation and the concept of pressure surfaces, indicating discrepancies in calculations leading to different results, specifically 0.1519 versus the expected 0.2255. The confusion arises from the interpretation of variables, particularly ζ, which is suggested to represent angular velocity.

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yecko
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Homework Statement
A closed cylindrical tank of 4 m in height and 2 m in diameter contains water to a depth of 3 m. When the cylinder is rotated at a constant angular velocity of 40 rad/s, show that nearly 0.71 m2 of the bottom surface of the tank is uncovered.
Relevant Equations
pressure surface, Bernoulli's equation
1607059199222.png

why is ro = 0.2255?
1607059272299.png


Thank you
 
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yecko said:
Homework Statement:: A closed cylindrical tank of 4 m in height and 2 m in diameter contains water to a depth of 3 m. When the cylinder is rotated at a constant angular velocity of 40 rad/s, show that nearly 0.71 m2 of the bottom surface of the tank is uncovered.
Relevant Equations:: pressure surface, Bernoulli's equation

View attachment 273668
why is ro = 0.2255?
View attachment 273669

Thank you
I would have assumed the handwritten calculation was yours, but your question implies it is someone else's. Please clarify.
 
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Sorry for being unclear.
The handwritten one is the answer written by prof. And the answer is same as final model answer in textbook.
However, when I substitute the number in the red bracket, I can only obtain 0.1519 from calculator instead of prof‘s answer 0.2255.
Have I done anything wrong? Thank you.
 
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yecko said:
Sorry for being unclear.
The handwritten one is the answer written by prof. And the answer is same as final model answer in textbook.
However, when I substitute the number in the red bracket, I can only obtain 0.1519 from calculator instead of prof‘s answer 0.2255.
Have I done anything wrong? Thank you.
OK, but you'll have to decipher the scrawl for me. It looks like ##\frac{64g}{\zeta^2}+4r_0^2=1##. If so, what is ##\zeta##?
 
1607081680932.png

From Kundu, by comparing the formula "Surfaces of constant pressure are given by ...", ζ written by Prof should be ω here, which implicates angular velocity. However, when I substite 40 rad/s, the answer is wrong. Am I having any misunderstanding with ζ?
 
for reference, this question is utilising the approach of "constant pressure surface"
1607082158657.png
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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