- #1

teknodude

- 157

- 0

When released into the U. S. Standard Atmosphere, at what altitude will it settle?

My first thought was that diagram has the weight of the balloon acting downward, buoyant force upwards.

-weight + Fb = 0

Fb = bouyant force

-mg + (specific weight of air)(h2-h1)A =0

My initial equation was this:

-mg - PA(pressure) + Fb = 0 but i believe this one is wrong.

The answer is 4000 m