Foci and the definition of a hyperbola

  • Thread starter Thread starter darshanpatel
  • Start date Start date
  • Tags Tags
    Algebra Conics
Click For Summary
SUMMARY

The discussion focuses on finding the equation of a hyperbola defined by the condition that the difference in distances from any point (x,y) on the hyperbola to the foci (2,2) and (10,2) is 6. The correct form of the hyperbola is established as opening horizontally, with the center at (6,2) and a distance of 4 units from the center to each focus. The equation is derived as \(((y-2)^2)/(b^2)-((x-6)^2)/(a^2)=1\), where the values of a and b need to be determined based on the relationship between the foci and the constant distance.

PREREQUISITES
  • Understanding of hyperbola geometry and properties
  • Familiarity with the standard form of hyperbola equations
  • Knowledge of distance formulas in coordinate geometry
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of hyperbola equations from distance definitions
  • Learn about the relationship between the foci, vertices, and asymptotes of hyperbolas
  • Explore the concept of eccentricity in hyperbolas
  • Practice solving problems involving hyperbolas with different focal points
USEFUL FOR

Students studying conic sections, mathematics educators, and anyone looking to deepen their understanding of hyperbolas and their properties.

darshanpatel
Messages
139
Reaction score
0

Homework Statement



Find an equation of a hyperbola such that for any point (x,y) on the hyperbola, the difference between its distances from the points (2,2) and (10,2) is 6.

Homework Equations



-None-

The Attempt at a Solution



I tried graphing it and making the (10,2) and (2,2) the vertices of the graphs. They open left to right because the points are horizontal to each other.

Equation for that type of circle: (y-k)^2/(a^2)-(x-h)^2/(b^2)=1

Distance between the two vertices =6 so center is (3,2)

I don't know what to do to get the a and b values because the equation right now would be:

(((y-2)^2)/(a^2))-(((x-3)^2)/(b^2))=1

Also is that right this far?
 
Physics news on Phys.org
I'll have to think a bit about the answer, but I can tell you right now that the answer isn't what you are describing. The vertices you are describing are 8 units apart, not 6 (10-2=8). Also, the midpoint of the x values of the line segment connecting the two points would be \frac{10+2}{2} = 6, so the midpoint would be (6,2), not (3,2).

Edit: Okay, I think I have it now. What are the two points in the plane called where, for every point on the hyperbola, the absolute value of the difference of the distance to each of those two points is a constant? How does that constant relate to the equation of the hyperbola?
 
Last edited:

Similar threads

Replies
4
Views
3K
  • · Replies 29 ·
Replies
29
Views
4K
Replies
7
Views
2K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K