Force and Motionfinding tension?

  • Thread starter Thread starter MetalAttack
  • Start date Start date
  • Tags Tags
    Force Tension
Click For Summary

Homework Help Overview

The problem involves an elevator cab being pulled upward by a cable, with a focus on determining the tension in the cable when a coin is dropped inside the cab. The subject area pertains to force and motion, specifically relating to tension and acceleration in a gravitational context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach finding the tension and seeks alternative wording for clarity. Some participants suggest summing forces to establish a relationship between tension, mass, and acceleration. Others clarify the meaning of variables and equations involved.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to set up the equations related to forces. There is an exploration of different interpretations of the variables involved, particularly regarding the definition of tension.

Contextual Notes

The original poster notes a lack of prior experience with problems specifically asking for tension, which may influence their understanding of the problem setup. There is also a mention of a free-body diagram being created to visualize the forces at play.

MetalAttack
Messages
4
Reaction score
0

Homework Statement


"Elevator cab is pulled upward by a cable. the cab and its one person inside weigh 2000kg.when that person drops a coin, its acceleration to the cab is 8.00m/s^2.
what is the tension in the cable?

I feel as tho i know what to do but the "tension" is throwing me off. I've never been asked to find it before. is there any other ways this might be worded for understanding?



Homework Equations


m=2000kg
Fx=MAx
Fy=MAy




The Attempt at a Solution


I am unsure how to add drawing in here. but basically i made a free-body-diagram.
with Fg(gravity) and a arrow pointing downwards. Fg=mg >> Fg=(2000)(9.81)= 19620
and with F or "N" for normal pointing upwards ^.

I am not looking for anyone to do this. just some hints and ideas as how to start :(
thank you
 
Physics news on Phys.org
you need to sum the forces; the sum of those forces must equal the net Force

Sum of the Forces in Y = T - mg = ma; where a is the acceleration of the whole system
 
fizzynoob said:
Sum of the Forces in Y = T - mg = ma; where a is the acceleration of the whole system
Fy= T -mg = ma
Fy= T = ma + mg
Fy= T = m(a+g)

T=time?
m=mass 2000kg
a=8.00m/s^2
g=-9.8a

correct?
 
T does not equal time, it is tension. Maybe i should of put Ft.

So you solved for T right, now you your acceleration and you know gravity. Plug in values
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K