(adsbygoogle = window.adsbygoogle || []).push({}); 1. The so-called Yukawa potential

(attached)

gives a fairly accurate description of the interaction between nucleons[that is, neutrons and protons, the constituents of the nucleus]. The constants r0 = 1.5x10-15metres and U0 = 50 MeV.[a] Find the corresponding expression for the force of attraction.

2. Fr= -dU/dr

3. When i finnaly calculate it, the answer is supposed to be negative because

Fr= - dU/dr

= - d (U is given negative)/dr

{ -ve and -ve cancels out }

Fr= +ve d(U)/dr

after integrating U, a -ve sign appears...

so...shouldnt the answer be negative? but the actual solution is a positive. can u tell me y ?

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# Homework Help: Force and Potential energy funtion

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