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1. The socalled Yukawa potential
(attached)
gives a fairly accurate description of the interaction between nucleons[that is, neutrons and protons, the constituents of the nucleus]. The constants r0 = 1.5x1015metres and U0 = 50 MeV.[a] Find the corresponding expression for the force of attraction.
2. Fr= dU/dr
3. When i finnaly calculate it, the answer is supposed to be negative because
Fr=  dU/dr
=  d (U is given negative)/dr
{ ve and ve cancels out }
Fr= +ve d(U)/dr
after integrating U, a ve sign appears...
so...shouldnt the answer be negative? but the actual solution is a positive. can u tell me y ?
(attached)
gives a fairly accurate description of the interaction between nucleons[that is, neutrons and protons, the constituents of the nucleus]. The constants r0 = 1.5x1015metres and U0 = 50 MeV.[a] Find the corresponding expression for the force of attraction.
2. Fr= dU/dr
3. When i finnaly calculate it, the answer is supposed to be negative because
Fr=  dU/dr
=  d (U is given negative)/dr
{ ve and ve cancels out }
Fr= +ve d(U)/dr
after integrating U, a ve sign appears...
so...shouldnt the answer be negative? but the actual solution is a positive. can u tell me y ?
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