Force and Potential Energy Graphs: Mastering Physics HW 11.39

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Homework Help Overview

The discussion revolves around the relationship between force and potential energy for a particle moving along the x-axis, specifically focusing on the graphical representation of potential energy as a function of position from x=0 to x=1.1, with the condition that potential energy is zero at x=0.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the integration of force functions to derive potential energy equations across different segments of the x-axis. There are questions about the continuity of the potential energy function and the correct application of integration constants.

Discussion Status

Some participants have provided guidance on ensuring continuity in the potential energy function and the importance of correctly determining integration constants. There is acknowledgment of mistakes in the integration process, and some participants express a sense of resolution after identifying errors.

Contextual Notes

Participants note that the potential energy function must be continuous and that the initial condition of U(0) = 0 imposes constraints on the constants derived from integration. There is an emphasis on the necessity of verifying calculations and constants at the boundaries of the defined segments.

Rimi
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Homework Statement


The figure below shows the force exerted on a particle that moves along the x-axis. Draw a graph of the particle's potential energy as a function of position from x=0 to x=1.1 . Let U be zero at x=0.

Homework Equations


F=-dU/dx

The Attempt at a Solution


I decided to divide the force graph into three separate graphs:

From x=0 to x=.5: F(x)= 4x
From x=.5 to x=1: F(x)= -4x + 4
From x=1 to x=1.1: F(x)= 0

I then integrated each equation, and multiplied them by -1, getting U(x)= -2x^2, U(x)= 2x^2 - 2 and U(x)= 0, respectively.

When I try to graph these equations, only the first one and the last one, U(x)= -2x^2 - 2 and U(x)= 0, seem to give me the correct answer. Can someone help me figure out where I went wrong?
 

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Rimi said:

Homework Statement


The figure below shows the force exerted on a particle that moves along the x-axis. Draw a graph of the particle's potential energy as a function of position from x=0 to x=1.1 . Let U be zero at x=0.

Homework Equations


F=-dU/dx

The Attempt at a Solution


I decided to divide the force graph into three separate graphs:

From x=0 to x=.5: F(x)= 4x
From x=.5 to x=1: F(x)= -4x + 4
From x=1 to x=1.1: F(x)= 0

I then integrated each equation, and multiplied them by -1, getting U(x)= -2x^2, U(x)= 2x^2 - 2 and U(x)= 0, respectively.

When I try to graph these equations, only the first one and the last one, U(x)= -2x^2 - 2 and U(x)= 0, seem to give me the correct answer. Can someone help me figure out where I went wrong?

Your U(x) should be continuous. If you define U(0) to be 0 then U(1) isn't 0. Adjust your constants.
 
Dick said:
Your U(x) should be continuous. If you define U(0) to be 0 then U(1) isn't 0. Adjust your constants.

Does that mean that U(x) would have to be an absolute value function?
 
Rimi said:
From x=0 to x=.5: F(x)= 4x
From x=.5 to x=1: F(x)= -4x + 4
From x=1 to x=1.1: F(x)= 0

I then integrated each equation, and multiplied them by -1, getting U(x)= -2x^2, U(x)= 2x^2 - 2 and U(x)= 0, respectively.
In each integral, you get an unknown constant. To figure out what the constant is for that integral, you have to plug in known values for U and x at the start of that range.
I don't see how you got 2-2x2 by integrating -4x+4.
 
haruspex said:
In each integral, you get an unknown constant. To figure out what the constant is for that integral, you have to plug in known values for U and x at the start of that range.
I don't see how you got 2-2x2 by integrating -4x+4.

It should read 2x^2 - 4x. My mistake.

And I forgot all about solving for the constant first...whoops! I figured it out, though. Thanks! ^.^
 

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