Force due to Solar Radiation and Gravity

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SUMMARY

The discussion centers on calculating the equilibrium radius of a small spherical particle in space, balancing gravitational force and solar radiation force. The gravitational force is defined by the equation F(g) = Gm1m2/r², while the solar radiation force is given by F(Solar) = C*S*I/c, where C = 1 for complete absorption. The participant's calculations yielded a radius of r = 790238.5 meters, but they were advised that the solar constant S was not properly incorporated into their calculations, indicating a need for correction in their approach.

PREREQUISITES
  • Understanding of gravitational force equations (F(g) = Gm1m2/r²)
  • Knowledge of solar radiation force calculations (F(Solar) = C*S*I/c)
  • Familiarity with mass density and volume relationships in spherical objects
  • Basic principles of equilibrium in physics
NEXT STEPS
  • Review the derivation of gravitational force equations in astrophysics
  • Study the impact of solar radiation pressure on small particles in space
  • Learn about the solar constant and its application in astrophysical calculations
  • Explore the relationship between mass density, volume, and equilibrium in spherical bodies
USEFUL FOR

Students in physics, astrophysics researchers, and anyone interested in the dynamics of small particles influenced by solar radiation and gravitational forces.

Mnemonic
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Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)

F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
 
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Mnemonic said:

Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)
Check that formula. Does mass really get smaller as the volume of the material gets larger?
F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
Nope. Besides the issue with the mass expression noted above, I don't see where the solar constant S is involved in your calculation.
 

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