Force due to Solar Radiation and Gravity

In summary: You need to find an expression for the force of solar radiation on the particle, set it equal to the gravitational force, and solve for r. Can you do that?In summary, we are given information about a small spherical particle located a distance R from the Sun and we need to find the value of r for which the particle is in equilibrium between gravitational force and solar radiation. Using the equations F(g)=Gm1m2/r2 and mass density=mass/volume, we can calculate the force of solar radiation and set it equal to the gravitational force. After solving for r, we get a value of 790238.5, but this calculation does not take into account the solar constant S. Therefore, the final
  • #1
Mnemonic
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Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)

F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
 
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  • #2
Mnemonic said:

Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)
Check that formula. Does mass really get smaller as the volume of the material gets larger?
F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
Nope. Besides the issue with the mass expression noted above, I don't see where the solar constant S is involved in your calculation.
 
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